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Semicircle Calculator

Area and perimeter of a half circle from its diameter — and the perimeter is the part people get wrong, because it includes the straight edge.

With diameter — the straight edge 8 ft, semicircle comes to 25.133 sq ft — area. It is reached in 6 steps, the last of which is full_area / 2, and each one is printed on the page with its numbers filled in. The formula is the one published by Wolfram MathWorld, not an approximation fitted to it.

Formula and sources checked · How we check

Diameter — the straight edge 8 ft

25.133 sq ft

Area for the example below. Editing a field recomputes the calculator below; this figure holds the answer the page was loaded with.

It is written into the HTML rather than drawn by a script, so a search engine reading this page without running JavaScript still finds an answer.

Area
25.133 sq ft
Radius
diameter / 24 ft
Area of the whole circle
pi * pow(radius, 2)50.265 sq ft
Area of the semicircle
full_area / 225.133 sq ft
Curved edge
pi * radius12.566 ft
Perimeter, including the straight edge
curved_edge + diameter20.566 ft
Centre of area, from the straight edge
4 * radius / (3 * pi)1.698 ft

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Worked example

An 8 ft semicircle covers 25.133 sq ft. Its perimeter is 20.566 ft — the 12.566 ft curve plus the 8 ft straight edge. Halving the circumference alone gives 12.566 and leaves out the side the arch actually sits on.

How to work it out yourself

  1. 1.Measure the straight edge: that is the diameter.
  2. 2.Halve it for the radius, then take π times the radius squared and halve that for the area.
  3. 3.For the curved edge alone, multiply π by the radius.
  4. 4.For the full perimeter, add the diameter back — the straight edge is part of the boundary.

The formula

  1. Radiusdiameter / 2
  2. Area of the whole circlepi * pow(radius, 2)
  3. Area of the semicirclefull_area / 2
  4. Curved edgepi * radius
  5. Perimeter, including the straight edgecurved_edge + diameter
  6. Centre of area, from the straight edge4 * radius / (3 * pi)

Source: Wolfram MathWorld — semicircle, NIST Digital Library of Mathematical Functions

Questions people actually ask

Is the perimeter just half the circumference?
No, and this is the usual mistake. Half the circumference is only the curve. The perimeter of the shape also includes the straight edge, so it is π × radius plus the diameter.
Where is the centre of a semicircle?
Not at the middle of the straight edge. The centre of area sits 4r/3π from it — about 0.42 of the radius — which matters when balancing or supporting an arched piece.

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